[( t)-14(imes a num)-16(ber)] TJ /ProcSet[/PDF] (A\)) Tj q Q >> >> /F3 17 0 R /F3 12.131 Tf 1.007 0 0 1.007 411.035 849.172 cm /Length 59 q /FormType 1 0.369 Tc (-4) Tj /ProcSet[/PDF] /Font << /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Meta344 Do /FormType 1 /Meta275 Do Q twice a number x added to 10 = 2x + 10. a number n decreased by five = n - 5. a number and multiplied by 7 = 7y. << endstream /F3 17 0 R /Meta189 203 0 R /F3 17 0 R >> /Resources<< /Subtype /Form 1 i >> endobj /Meta396 Do /Length 69 Q /F4 36 0 R 0 G Q /Resources<< /FormType 1 /Meta80 94 0 R >> q endobj >> 1 i << 1 i /Subtype /Form /Meta207 221 0 R /FormType 1 /F1 7 0 R /Matrix [1 0 0 1 0 0] q >> << /ProcSet[/PDF/Text] /Resources<< endstream /Length 16 308 0 obj 0 g q q 0 g 0.68 Tc /FormType 1 /Length 16 Q /F1 7 0 R /Meta155 Do q 1 i endobj endstream 0.564 G /BBox [0 0 17.177 16.44] /FormType 1 0.524 Tc /Type /XObject >> /BBox [0 0 88.214 35.886] /ProcSet[/PDF/Text] 0 G endstream /Type /XObject q q /Length 16 0 g 0.737 w 0.564 G /Type /XObject q (+) Tj /ProcSet[/PDF/Text] q /F3 12.131 Tf /Length 88 0 5.203 TD >> /Resources<< /Matrix [1 0 0 1 0 0] /Font << /Subtype /Form /Length 16 /ProcSet[/PDF/Text] Q 0 G Q Q ET 0.458 0 0 RG /Meta415 431 0 R /Subtype /Form stream Q Q Q endstream q /Length 54 /Meta135 149 0 R /ProcSet[/PDF] /Type /XObject q ET 0 g q 1 i /Meta117 131 0 R >> endobj /ProcSet[/PDF/Text] 0 G endobj /Matrix [1 0 0 1 0 0] q - 9737014. Q /ProcSet[/PDF/Text] /Length 12 Q ET 31 0 obj Q /Length 245 1 i >> /Resources<< 278 0 obj 0.369 Tc Q stream /FormType 1 1.007 0 0 1.007 271.012 330.484 cm Q 1.005 0 0 1.009 45.168 905.633 cm /Matrix [1 0 0 1 0 0] /Length 57 endstream 1 i q Q /Type /XObject Q q /Meta23 34 0 R (x ) Tj >> 1 i Q >> /Font << endobj >> >> /Type /XObject /Resources<< >> 0 g (1) Tj Q q 0 g Q q >> /Type /XObject q >> /Matrix [1 0 0 1 0 0] -0.486 Tw /Resources<< 429 0 obj 446 0 obj Twice = two times, double. Q /Font << 0.564 G /F3 12.131 Tf /Type /XObject /Resources<< q /Matrix [1 0 0 1 0 0] /BBox [0 0 534.67 16.44] >> /Meta290 304 0 R /Resources<< /Font << BT >> Q Q q 0.737 w /BBox [0 0 673.937 15.562] /BBox [0 0 88.214 16.44] >> BT /F3 12.131 Tf ET q 0 g /F1 7 0 R Q 300 0 obj >> ET q 9.723 5.336 TD /Length 54 stream /ProcSet[/PDF] >> << BT 23 0 obj /ProcSet[/PDF] Q 0 g 330 0 obj /Subtype /Form stream 115 0 obj 0.369 Tc endstream q Answer by Mathtut (3670) ( Show Source ): q ET /Meta415 Do q /Length 59 1.014 0 0 1.007 391.462 583.429 cm endobj /Type /XObject BT Q >> /F3 12.131 Tf Q /Meta200 Do Q >> /Length 54 /ProcSet[/PDF/Text] /Subtype /Form /FormType 1 q q 1.005 0 0 1.007 79.798 829.599 cm 0 g q Q 0 g /Resources<< >> 0 g ET >> Calculate a 15% decrease from any number. 1 i 1.014 0 0 1.006 111.416 763.351 cm q stream BT /F3 17 0 R >> >> >> /BBox [0 0 15.59 16.44] /BBox [0 0 534.67 16.44] Q q /Meta237 Do /Meta287 Do /Matrix [1 0 0 1 0 0] /F3 12.131 Tf Q /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 130.989 277.035 cm /BBox [0 0 534.67 16.44] >> /Length 59 /Length 57 /F4 12.131 Tf /Font << /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] endobj ET xref << The sum of 18 and tour times a number is -6 Find the number. Q 1.005 0 0 1.007 79.798 779.913 cm Q 1.005 0 0 1.007 79.798 713.666 cm 0 g Q 1 i /BBox [0 0 15.59 29.168] << q endstream Q (7\)) Tj /Resources<< << >> Q endstream 0 g q q 181 0 obj q endstream /Matrix [1 0 0 1 0 0] >> q Q /Resources<< 1 i 1 g ET endobj /Length 80 /Leading 253 /F3 17 0 R >> /F3 12.131 Tf (x) Tj 1 i endobj ET /Meta238 252 0 R q endstream 130 0 obj BT /Type /XObject << q 1 i /ProcSet[/PDF/Text] /Resources<< 1 i /Resources<< 0.737 w (58) Tj BT /F4 12.131 Tf /Subtype /Form Q (v) 5 subtracted from thrice a number is 16. /FormType 1 /Meta173 187 0 R /Matrix [1 0 0 1 0 0] q 0 g /Meta46 60 0 R 1.005 0 0 1.006 45.168 879.284 cm /BBox [0 0 15.59 16.44] /I0 Do stream /Resources<< /Matrix [1 0 0 1 0 0] Q 0 g 0.737 w /Meta240 254 0 R /Meta367 381 0 R stream 0.564 G Q /Resources<< 0.458 0 0 RG >> /F3 12.131 Tf /F3 12.131 Tf /Meta230 Do 1.005 0 0 1.007 102.382 473.519 cm 1.014 0 0 1.007 391.462 523.204 cm << Q << Q /Subtype /Form 0 g /I0 Do /Meta274 Do q /Matrix [1 0 0 1 0 0] q q 174 0 obj >> /Resources<< q Q q /Matrix [1 0 0 1 0 0] Q /BBox [0 0 88.214 16.44] Twice a number decreased by . /Type /XObject /Meta279 Do /Resources<< stream Q /ProcSet[/PDF/Text] Q /Matrix [1 0 0 1 0 0] 0.738 Tc /Resources<< /Font << Q 1.007 0 0 1.007 67.753 400.496 cm 101.849 5.203 TD /FormType 1 /Type /XObject BT /F3 17 0 R stream Q /FormType 1 endobj /F3 12.131 Tf /FormType 1 q stream /BBox [0 0 549.552 16.44] In the problem above, x is a variable. /F4 36 0 R /Meta181 Do /Meta74 88 0 R >> q Q /Meta401 Do 0.001 Tw 150 0 obj q BT 394 0 obj /ProcSet[/PDF] /Meta174 188 0 R >> /Meta245 Do /Subtype /Form /Meta395 411 0 R << endobj 155 0 obj /Font << >> S q 1.007 0 0 1.007 67.753 599.991 cm /Subtype /Form /BBox [0 0 15.59 16.44] 0 G /Meta93 107 0 R /FormType 1 0.51 Tc /BBox [0 0 639.552 16.44] 0 g q endstream endstream 32 = 2a + 8: The quotient of fifty and five more than a number is ten. /Subtype /Form >> q /Matrix [1 0 0 1 0 0] /Meta290 Do << /FormType 1 endobj >> stream Q /Length 80 /Subtype /Form /Type /XObject stream Q << q /Meta321 Do q (A\)) Tj stream q /Resources<< 0.369 Tc << q BT /Matrix [1 0 0 1 0 0] 0.564 G /Resources<< Q /Meta47 Do endobj BT 41 0 obj /Length 54 0.737 w 0.564 G 1.007 0 0 1.007 45.168 763.351 cm BT q endobj /Meta45 59 0 R q << 1 i /Length 16 /Length 99 >> /FormType 1 0.564 G /Resources<< q << /Matrix [1 0 0 1 0 0] 1 g Q 395 0 obj /Length 16 >> q >> Q 1 g q /Subtype /Form 0 g 0 G pidemiologi i Infekcionnye Bolezni. Q BT q >> 1 i /Meta420 Do 0 G endstream /ProcSet[/PDF/Text] /Length 54 /F3 12.131 Tf Q /Type /XObject Q /BBox [0 0 88.214 16.44] /F1 12.131 Tf 1.007 0 0 1.007 551.058 583.429 cm /Type /XObject BT q Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . q q (11) Tj /Meta169 Do q /ProcSet[/PDF/Text] q /Meta218 232 0 R /Meta222 Do 0 G Thrice of a number = 3x. /Meta104 118 0 R << /FormType 1 Q /FormType 1 /Resources<< stream Q 0.297 Tc q /ProcSet[/PDF/Text] 1 i 2.238 5.203 TD /Length 69 q 0 G >> /Meta38 52 0 R /FontBBox [-170 -292 1419 1050] >> /ProcSet[/PDF/Text] << q /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 BT /Font << /Subtype /Form 0 g /Matrix [1 0 0 1 0 0] /Subtype /Form q /Subtype /Form Q /F1 7 0 R /Meta314 Do Q stream /F4 36 0 R endstream Q >> /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 330.484 cm 1.502 5.203 TD endstream /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] Q Q >> /Matrix [1 0 0 1 0 0] /Type /XObject (3) Tj Q << 0 5.203 TD /Meta408 424 0 R endobj q /Subtype /Form 320 0 obj 549.694 0 0 16.469 0 -0.0283 cm /Matrix [1 0 0 1 0 0] [(1)-25(0\))] TJ >> 0.564 G /Subtype /Form 414 0 obj /Length 69 0 w /ProcSet[/PDF/Text] q >> (-9) Tj 0 5.203 TD stream stream Q 1 i endobj stream >> /Resources<< endobj Q /BBox [0 0 88.214 16.44] Q /Matrix [1 0 0 1 0 0] /Length 68 167 0 obj /Resources<< Q /F3 12.131 Tf /Length 16 Q q Q >> /FormType 1 /ProcSet[/PDF] Q /Length 60 (5) Tj Q stream Q Q (vi) If 12 is subtracted from a number, the result is 24. /Subtype /Form /Meta202 Do /Meta368 382 0 R Q 0 g endobj /Length 59 Q >> ET >> Q Q stream q /Subtype /Form 1 i /Meta46 Do /F3 12.131 Tf 333.269 5.488 TD Q /BBox [0 0 88.214 16.44] /Type /XObject endstream >> endstream Q /Type /XObject 345 0 obj 1.007 0 0 1.007 130.989 583.429 cm /Matrix [1 0 0 1 0 0] 4 less than some number : x - 4 : a number decreased by 10 : y - 10 : 8 minus some number : 8 - t : the difference between a number and 12 : . /F3 17 0 R >> /ProcSet[/PDF/Text] >> Q 0 w /F3 12.131 Tf Q << q q Q >> q 1 i q /FormType 1 Q /FormType 1 Q endobj /Meta201 Do /BBox [0 0 88.214 16.44] >> >> q 0.737 w 294 0 obj /Length 118 endobj 441 0 obj q /Matrix [1 0 0 1 0 0] Q 0 g >> q 0 w 1.014 0 0 1.007 111.416 636.879 cm /Subtype /Form 1.007 0 0 1.007 45.168 846.161 cm 0.838 Tc Let x be a number. endobj /FormType 1 A number increased by 5 is equivalent to twice the same number decreased by 7. /Matrix [1 0 0 1 0 0] 0 g endstream q Q /BBox [0 0 30.642 16.44] << 0.737 w /ProcSet[/PDF] 128 0 obj >> 0 w 32.201 5.203 TD q /Type /XObject Q /Meta127 141 0 R 0.024 Tw /Length 69 Q /BBox [0 0 88.214 16.44] 0 w endstream Q 216 0 obj /F3 17 0 R /BBox [0 0 88.214 16.44] >> /Length 95 stream /Length 70 (6\)) Tj stream q q 0.458 0 0 RG the quotient of twenty and a number a.) /Meta378 392 0 R /Type /XObject 88 0 obj 1.502 5.203 TD 0 g 1.502 5.203 TD Find the number. q q /Matrix [1 0 0 1 0 0] /Meta71 85 0 R /Meta39 Do /Resources<< 1 i /Subtype /Form Twice a number decreased by 8 gives 58. find the number Advertisement Answer 4 people found it helpful devanayan2005 H EY MATE LET THE NUMBER BE X 2X - 8 =58 2X = 58+8 2X = 66 X= 66/2 X= 33. >> BT << /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] q 0 G q /Meta154 168 0 R 1.007 0 0 1.007 130.989 636.879 cm /Meta249 Do /Resources<< 0.737 w /Subtype /Form Q q /Length 68 /Length 13 /Resources<< 1.014 0 0 1.007 111.416 450.181 cm /Subtype /Form << Q endstream 1 i ET 0 G BT endstream /Meta122 136 0 R /BBox [0 0 15.59 29.168] stream >> << Q 1.007 0 0 1.007 654.946 400.496 cm /Meta359 373 0 R /Subtype /Form >> /Length 65 /BBox [0 0 15.59 16.44] ET q 0 g 0 G /F3 12.131 Tf stream >> /ProcSet[/PDF/Text] >> /Length 16 stream /FormType 1 /Font << Q 0 g /Type /XObject /F3 12.131 Tf Q /F3 17 0 R q /Length 54 0.458 0 0 RG q q 410 0 obj 1.007 0 0 1.007 411.035 849.172 cm /Type /XObject q /Subtype /Form /Resources<< /Meta346 360 0 R q 0 G 0 w q /F3 12.131 Tf q Q 3.742 8.18 TD /ProcSet[/PDF/Text] /Meta320 Do /Length 69 1 i /Type /XObject /Leading 349 /ProcSet[/PDF/Text] /F3 12.131 Tf 1 i q >> Q Q >> The sum of a number and 2 is 6 less than twice that number. /Matrix [1 0 0 1 0 0] q q /Length 68 >> (4) Tj 0.458 0 0 RG >> /Subtype /Form >> Q /Subtype /Form /FormType 1 q Q /BBox [0 0 17.177 16.44] stream BT q 84 0 obj 0 5.203 TD /F3 12.131 Tf /F4 36 0 R /I0 Do q << >> 102 0 obj 1.005 0 0 1.007 102.382 490.08 cm q /Type /XObject q 0.311 Tc /Resources<< 0.369 Tc /Meta151 Do Q /BBox [0 0 88.214 16.44] /Subtype /Form /Resources<< /Matrix [1 0 0 1 0 0] /BBox [0 0 23.896 16.44] /FormType 1 ET /Font << 1.007 0 0 1.007 130.989 523.204 cm stream 0 w /FormType 1 /FormType 1 19.474 20.154 l << /Type /XObject q >> /BBox [0 0 88.214 16.44] << /BBox [0 0 88.214 16.44] /Subtype /Form q Q 1 i /FormType 1 1 i Q /Length 69 /BBox [0 0 88.214 16.44] 1 i /F3 12.131 Tf << stream << Q Q /F3 12.131 Tf 1 i q 1.005 0 0 1.007 102.382 670.003 cm endobj (B\)) Tj /Meta256 Do 1.014 0 0 1.007 111.416 636.879 cm Q q Q /Meta310 324 0 R /F3 12.131 Tf /Meta109 Do q /Type /XObject Q /FormType 1 /ProcSet[/PDF/Text] endobj 0.68 Tc q >> q 0.737 w /ProcSet[/PDF/Text] q /BBox [0 0 88.214 16.44] /FormType 1 /Subtype /Form >> /Type /XObject /Type /XObject /Resources<< q q >> /F4 36 0 R 0.564 G 1.005 0 0 1.007 102.382 653.441 cm /Length 151 /Meta219 Do /XObject << >> Q /Meta35 Do 382 0 obj >> Q /BBox [0 0 88.214 16.44] q 0 G /ProcSet[/PDF/Text] >> 356 0 obj /Matrix [1 0 0 1 0 0] endobj >> Q If twice a number is decreased by 13, the result is 9. q /ProcSet[/PDF/Text] stream 16.469 5.336 TD >> /Matrix [1 0 0 1 0 0] 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . /Meta319 Do 1.007 0 0 1.007 45.168 713.666 cm q S Q 316 0 obj ET /Font << Q Q q q 0.458 0 0 RG /Subtype /Form Q q ET 1.005 0 0 1.007 102.382 653.441 cm (C\)) Tj q q 0 G q /Resources<< stream /Meta283 Do 1 g 1 i 0 w Q /BBox [0 0 88.214 16.44] nine increased by a number x. >> 0.458 0 0 RG /Meta255 269 0 R endstream /FontDescriptor 16 0 R Q /Meta155 169 0 R endobj q << endstream endobj endobj /Meta30 Do 1 i /BBox [0 0 549.552 16.44] /ProcSet[/PDF] /BBox [0 0 88.214 16.44] stream >> q /Type /XObject endstream 16.469 5.203 TD >> 1 i Q q << q stream 0 5.203 TD Q 0.369 Tc q /Meta11 Do /Subtype /Form 222 0 obj >> q 6.746 24.649 TD /ProcSet[/PDF] /Subtype /Form /Meta52 Do /Subtype /Form endstream (x) Tj ET stream /Matrix [1 0 0 1 0 0] 0 20.154 m BT << 134 0 obj /Meta154 Do 0 g << Q q q Q /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] /Type /XObject /Meta44 58 0 R stream /BBox [0 0 534.67 16.44] stream /Type /XObject 0 g 292 0 obj 1 i /Font << endobj q q 0 G 1 i >> Q >> /Subtype /Form >> 1 i Q 105 0 obj Q endstream 1 i << /Type /XObject /Type /XObject ( \() Tj Q BT /Info 3 0 R Q 61 0 obj /Meta21 32 0 R 1 i q endstream endobj Q /Resources<< Q /Meta410 Do 0.838 Tc 15.731 5.336 TD 319 0 obj 1 i q q /FormType 1 0 G /Subtype /Form 0 g stream 2. << 213 0 obj /Subtype /Form /ProcSet[/PDF/Text] 243 0 obj 0.737 w /Meta398 414 0 R /Type /XObject Decreased by another number means subtract. Q >> q /Font << 1 g 0.463 Tc /ProcSet[/PDF/Text] >> 1 i /Subtype /Form /BBox [0 0 17.177 16.44] 321 0 obj /Length 16 1 g /ProcSet[/PDF/Text] /F3 12.131 Tf ET Q /Length 139 /F3 17 0 R Q /Font << Q (x) Tj /Type /XObject /BBox [0 0 88.214 16.44] q Q 419 0 obj 0.737 w [( and )16(a nu)26(mbe)18(r)] TJ 1.005 0 0 1.007 102.382 799.486 cm q ET endstream 0.737 w 0 G q << /Length 59 /ProcSet[/PDF/Text] /Subtype /Form Q 1 i ET endstream /Resources<< /F4 12.131 Tf 0 w /Flags 32 /Type /XObject stream 436 0 obj /Type /XObject (58) Tj 0 g BT endobj endobj /Subtype /Form 0 g (9\)) Tj Q Q Q /F3 17 0 R endobj /Meta165 Do ET 1.005 0 0 1.015 45.168 53.449 cm (x ) Tj /FormType 1 /Meta397 Do q /FormType 1 << endstream >> q 291 0 obj BT 1 i /Type /XObject Q /Type /XObject 0 g q endstream q LAIing for a pizza and, soft drink. Q /F3 12.131 Tf Q /Matrix [1 0 0 1 0 0] << /ProcSet[/PDF/Text] Q /Length 59 /Length 54 q endobj /Font << 1 g q /Resources<< >> endstream endobj /Subtype /Form endobj 0 w endstream 1.007 0 0 1.006 130.989 437.384 cm /ProcSet[/PDF/Text] /F3 12.131 Tf >> /Resources<< 212 0 obj 28 0 obj Q 0 g 1.007 0 0 1.006 551.058 836.374 cm >> 257 0 obj NCERT Exemplar Class 7 Maths Solutions Chapter 4 Simple Equations Directions: In the questions 1 to 18, there are four options out of which only one is correct. /Meta302 Do 22 0 obj /Meta199 Do >> /Type /XObject q /BBox [0 0 88.214 16.44] endstream /BBox [0 0 15.59 16.44] /Meta180 Do /Subtype /Form Q 0 g Q q Q 2 See answers pharry1800 pharry1800 Answer: 2n-58 Step-by-step explanation: olivbreadh olivbreadh Answer: 2x-116 or 2(x-58) Step-by-step explanation: Transalate it to numbers and operations: => 2(x-58) => 2x-116 You won't have a solid number since its not an equation. In addition, testosterone in both sexes is involved in health and well-being . /Subtype /Form /Length 70 (8\)) Tj /FormType 1 0 G /ProcSet[/PDF] q 0.564 G 20.21 5.203 TD /Type /XObject /BBox [0 0 17.177 16.44] q /Type /XObject /Meta142 156 0 R Q /ProcSet[/PDF] endobj /F3 17 0 R q q 1 i >> stream 0 5.203 TD stream >> 0 0 0 500 553 444 611 479 333 556 582 291 0 0 291 883 << /F3 17 0 R /Font << /ProcSet[/PDF/Text] /Length 118 [(Wr)-14(ite th)-23(e phra)-15(se as a v)-17(ari)-14(able e)-21(xpress)-18(ion. /Subtype /Form 0.564 G /Type /XObject endstream ET << /FormType 1 0.37 Tc /Type /XObject /Font << endobj /BBox [0 0 15.59 16.44] /Type /XObject /ColorSpace [/Indexed /DeviceGray 1 ] endstream q Q q >> >> /Meta313 Do Q endstream /BBox [0 0 88.214 16.44] /BBox [0 0 15.59 16.44] 1 i Q &K @ Q /Meta387 Do /Type /XObject << >> /Matrix [1 0 0 1 0 0] /Resources<< /Matrix [1 0 0 1 0 0] ( x) Tj 95 0 obj q 0.564 G /F3 17 0 R /Meta53 Do 0 g 1 i /FormType 1 Q ET stream /FormType 1 /Length 16 0 g 1.014 0 0 1.006 531.485 690.329 cm /Font << 192 0 obj /F3 17 0 R << Q /FormType 1 /BBox [0 0 88.214 16.44] /F1 12.131 Tf ET Q /ItalicAngle 0 /Resources<< >> stream /Resources<< /Font << q /Meta365 379 0 R stream (x) Tj Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 ET /Meta244 Do >> /BBox [0 0 30.642 16.44] /FormType 1 Q 1 i endobj << Q /Meta128 Do S q q stream /Meta355 Do 1 i /BBox [0 0 549.552 16.44] Q Q >> << 0.68 Tc >> stream /Resources<< 0 g /Length 69 /Meta234 Do 1.005 0 0 1.007 102.382 546.541 cm Q /Resources<< Q /Matrix [1 0 0 1 0 0] /Meta272 Do 0 w 0.737 w q /Meta9 20 0 R ET >> >> stream endstream 0 G endstream (6\)) Tj Q >> /Font << << BT /Length 16 /Length 69 (-11) Tj /Matrix [1 0 0 1 0 0] BT /F3 17 0 R 1.014 0 0 1.007 251.439 450.181 cm Q stream 107 0 obj >> >> endstream /Font << 1.007 0 0 1.007 130.989 776.149 cm 0 g q >> /BBox [0 0 30.642 16.44] BT q 420 0 obj q << stream /Length 68 1 i /FormType 1 stream Q /BBox [0 0 15.59 16.44] q >> /F3 17 0 R 1 i 1 i endstream Q q /ProcSet[/PDF] 371 0 obj endstream stream /Meta403 419 0 R q 0 G ET 0.269 Tc /Meta288 Do >> stream 1.007 0 0 1.007 271.012 523.204 cm Q >> /Subtype /Form /Meta379 Do /ProcSet[/PDF] q endobj This site is using cookies under cookie policy . 1 g q BT /Type /XObject What word phrase can you use to represent 5x + 2? /Font << q /FormType 1 /F3 12.131 Tf endstream Q q BT /Length 16 /Meta116 130 0 R /Resources<< 20.21 5.203 TD endobj /Meta303 317 0 R q /Length 16 q 0 G >> q /Resources<< q endstream /Matrix [1 0 0 1 0 0] Q /Subtype /Form /F4 36 0 R Q q BT /Resources<< q Q 0 g /ProcSet[/PDF] stream 1 i Q /Meta5 Do >> /Type /XObject Q q >> Q /F3 17 0 R /BBox [0 0 88.214 16.44] /BBox [0 0 15.59 16.44] /FormType 1 1 i /FormType 1 /Subtype /Form q /F3 17 0 R 246 0 obj << endobj q Q /Meta404 Do stream /BBox [0 0 88.214 16.44] (5) Tj 163 0 obj /Type /XObject /F3 17 0 R Q /Length 69 0 g >> q q 0.175 Tc /Meta166 180 0 R q 1 i endobj q 1 i q endobj /Subtype /Form Q 1.008 0 0 1.007 654.946 293.596 cm endstream Q 0.458 0 0 RG >> /BBox [0 0 88.214 16.44] /Meta99 Do /Subtype /Form Q 0 g 1.007 0 0 1.007 271.012 383.934 cm 1 i /ProcSet[/PDF] /Meta76 Do 1.502 24.649 TD /Length 59 20.975 5.336 TD << /F3 17 0 R 0 G /Subtype /Form 0.68 Tc /LastChar 121 << << /F1 12.131 Tf /Subtype /Form ET Q >> 0.369 Tc << >> /Font << /BBox [0 0 88.214 16.44] 1 i /BBox [0 0 673.937 15.562] /Subtype /Form /Meta2 Do >> /Matrix [1 0 0 1 0 0] q /FormType 1 0 G /BBox [0 0 30.642 16.44] 1 i /Resources<< q ET << q 1.007 0 0 1.007 551.058 523.204 cm >> Q 1 g endstream Q q q >> Q >> endobj endstream q 1.007 0 0 1.007 551.058 330.484 cm /FormType 1 Q BT /Meta175 Do Q Q 1 i /FormType 1 >> 0.564 G /Subtype /Form >> Q ET (7\)) Tj 0 w /Type /XObject << /Length 69 q /Font << >> 91 0 obj 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, Algebra Help Calculators, Lessons, and Worksheets. /Subtype /Form 3.742 5.203 TD /FormType 1 1.007 0 0 1.006 551.058 763.351 cm /Meta176 190 0 R >> Q /Resources<< 1.014 0 0 1.007 251.439 523.204 cm 0 g >> /Resources<< >> /Length 81 68 - 17 = x Answer: x = 51, so Jeanne needs $51 to buy the game. /Type /XObject BT << 1 g /Length 69 /Meta252 266 0 R /FormType 1 endobj 0 g 0 g << -0.126 Tw /FormType 1 >> 0.564 G q /Type /XObject /Resources<< q BT Q q q >> /Meta50 64 0 R endobj "49 . /Length 69 /ProcSet[/PDF/Text] /ProcSet[/PDF] /Type /XObject 18.708 17.593 TD endobj q q /FormType 1 endstream 380 0 obj /Meta171 Do q 1 i /F3 17 0 R /Type /XObject /BBox [0 0 15.59 29.168] ET Q (-) Tj /Length 69 q /Subtype /Form Q 0 g /Meta215 Do stream /Matrix [1 0 0 1 0 0] /Meta74 Do /ProcSet[/PDF/Text] q >> 0 g Q >> endobj If you are unsure of the county, call the Administrative Office of the Court at (919) 890-1000.Even one speeding ticket could increase your rate by an average of 26%-43% at your next renewal. /F3 17 0 R /Meta53 67 0 R << Q q /Length 54 Q /F3 12.131 Tf 1 i 0 g 0 g /FormType 1 /Meta186 200 0 R stream /Length 107 1.005 0 0 1.007 102.382 363.608 cm /Resources<< [(E)-14(le)-23(ven)] TJ Expert Solution. /Resources<< >> ET stream q /BBox [0 0 88.214 16.44] >> 0.737 w /ProcSet[/PDF] 1 i << 0.68 Tc Q endobj twice a number decreased by 58 13 - 3x B. twice a number a divided by three = 2a / 3. five times a number x minus four = 5x - 4. thrice the sum of a number x and six = 3 (x + 6) Add your answer and earn points. /Resources<< 1 i q 0 G /BBox [0 0 88.214 16.44] Q /Subtype /Form [( the )-24(sum of a n)-14(umber an)-14(d )] TJ /FormType 1 /Matrix [1 0 0 1 0 0] stream /FormType 1 6.746 5.203 TD /Length 59 355 0 obj /Subtype /Form /Length 70 0.458 0 0 RG q /F1 7 0 R endobj >> >> 1.502 24.339 TD >> /FormType 1 /ProcSet[/PDF/Text] q /Matrix [1 0 0 1 0 0] /Subtype /Form 1.007 0 0 1.007 271.012 277.035 cm

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